PRIEST IN WELL Arithmetic Progression A temple priest in dawn, fell into the bottom of the huge agricultural well and during day he is able to climb up 10’ but when it is dark he slips through nine’. In how many days, he would be out of the well? The well is 20’ deep. THOSE WHO GET CORRECT ANSWER CAN PAT ON THEIR BACK ON BEHALF OF .?
Day 1 - 10' - 9' = 1' Day 2 - 1+10 - 9 = 2' Day 3 - 2 + 10 - 9 = 3' and so on - on Day 9, he has reached 9' Day 10 - 9 + 10 - 9' = 10' Day 11 - 10' + 10 = 20' -> he is out so he will be out on day 11 Where is the pat on my back ?
That is Noble for Teacher! Regards. Thread in link Eienstein Problem On Speed Would perhaps interest you.