Imagine a very long belt encircling the world along the equator. We add some extra length to the belt so that the belt is standing at a height of one metre above the ground everywhere, that is, through out its length. If so what is the magnitude of the extra length added ?
If one assumes Earth is a spheroid then let R be radius of it. The belt all around equator at a height of one meter above radius of belt circle is R+1 meters. Belt length = 2pi (R+1) equator circumference = 2piR. Difference between the lengths = extra length added to the belt = 2pi(R+1) - 2piR = 2piR + 2pi - 2piR = 2pi = 2x22/7 =44/7 meters! But then the catch is how would hold the belt over the ocean part of the planet earth. also along the path there could be tall mountains making it impossible to hold the belt above one meter from earth surface. Thanksandregards.
