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But then how to arrive at figure 369. The zigma of total collectable milk from the entire group of ciws would be 1+2+3+....+81 which is sum of natural numbers . Using arithmetic progression summation formula

81 x 82 divided by 2
Would give 3321
Which divided among
Nine sons
Would result in qty of milk
Per son
By his set of allocated cows
369​

Then arrange an array of 9 x 9 numbers one to eighty one to get total

369​

​

 

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